<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Here the graph and what else you need
Answer:
x-ints: (2,0) & (4,0)
y-int: (0,-8)
vertex: (3,1) *highest point of the graph
line of symmetry: x = 3 *x-value in the middle of x-ints
a value is -# *if parabola points done it's negative, if it points up it's positive
Answer:
Simple.
The decimal 0.5555 is a rational number. It's a terminating decimal, since it doesn't end with an ellipsis.
Y = 1.25x + 30 <== ur function
for 3 hrs.....x = 3
y = 1.25(3) + 30
y = 3.75 + 30
y = 33.75 <=== for 3 hrs
