Answer: 
Explanation:
let this sign be ∅ (titha in degrees)
let coefficient of friction of 0.200 be u
and i be current i= 1.41A
mass m=1.14g/cm m=0.0114g/m
To find the magnetic field from the north will be:
tan ∅= u
∅=
∅=11.3°
The direction:
i L*B cos(∅)= umg
divide both by iLcos(∅) to find B
B= 
where m=
B= 
B= 
FALSE!!! exercise is great for all systems!!
This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.
Explanation:
power=f×v. recall= distances/ time
= f× d/t
= 30 × 2/5
=12watt
Answer;
=0.43 m/s²
Solution;
There will be the tension in the cable, T, upwards and the weight of the elevator, mg, downwards.
By Newton's second law, the sum of the forces will be equal to mass×acceleration.
Resultant force = m × a
Then T - mg = ma so the tension in the cable is
T = m(g+a)
The cable will break when T = 21,800 N
Solving for a, that happens when
a = 21800/2130 - g
= 10.23 - g (in m/s^2)
If you're using g = 9.8 m/s^2
Then the maximum acceleration allowed is 10.23-9.8 = 0.43 m/s^2
