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4 years ago

A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?

Physics

1 answer:

Makovka662 [10]4 years ago

5 0

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length $f=\frac{R}{2}=\frac{12}{2}=6cm$

Now for mirror we know that $\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

So $\frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}$

$16.66-0.333=\frac{1}{v}$

v = 0.750 m

Now magnification of the mirror is $m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025$

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A horse canters away from its trainer in a straight line, moving 37 m away in 9.1 s. It then turns abruptly and gallops halfway

vesna_86 [32]

Answer:

Average velocity = 1.69 m/s

Average speed = 5.09 m/s

Explanation:

Given that

Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.

As we know that

Average velocity = Displacement / Total time

Average speed = Total distance / Total time

Average velocity:

Average velocity = Displacement / Total time

Total displacement = 37 - 18.5 = 18.5 m

Total time = 9.1 + 1.8 =10.9 s

Average velocity = Displacement / Total time

Average velocity = 18.5 / 10.9

Average velocity = 1.69 m/s

Average speed:

Average speed = Total distance/ Total time

Total distance = 37 + 18.5 = 55.5 m

Total time = 9.1 + 1.8 =10.9 s

Average speed = Total distance/ Total time

Average speed = 55.5 / 10.9

Average speed = 5.09 m/s

3 0

3 years ago

Compare and contrast inference and critical thinking

fgiga [73]

Critical Thinking means to rush to find a solution for a problem - Inference means to having a conclusion to the situation you were facing.

What they both have in common is that if you are facing a problem, you have to come up with a good solution so that you would have a conclusion to the problem you had in the first place.

5 0

3 years ago

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

Elina [12.6K]

The answer is letter C.

Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.

The force of attraction between any two masses is called Newton's Law of Universal Gravitation:

$G \frac{m_1m_2}{d^2}$

$G$ is simply a given constant.

If we're at the surface of Eath, $m_1$ refers to the mass of the Earth, $m_2$ to the mass of whatever is on the surface of Earth, and $d$ to the radius of Earth.

Normally, we define a constant $g$ to be equal to $G \frac{M}{r^2}$ ; in which $M$ is the mass of Earth and $r$ the radius of earth; $g$ happens to be around 9.8.

By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

$W=mg$

As you can see, weight is directly proportional to mass, more mass implies more weight.

8 0

4 years ago

Electrons of wavelength 1.5 nm are emitted from a material when light of wavelength 350nm is incident on it. What is the work fu

krok68 [10]

Answer:

3.5434 eV

Explanation:

For a particle with kinetic energy E and mass m , the wavelength associated is given by the following relation,

$\lambda=\frac{h}{\sqrt{2mE} }$