All categories

2 years ago

A bicyclist travels at the speed of 25 kilometers per hour for 5 hours. How far does the bicyclist go?

Physics

2 answers:

Andreas93 [3]2 years ago

8 0

Answer:

$\boxed {\boxed {\sf 125 \ kilometers}}$

Explanation:

Distance is the product of speed and time.

$d=s*t$

The speed of the bicyclist is 25 kilometers per hour. The time is 5 hours.

$s= 25 \ km/hr \\t= 5 \ hr$

Substitute the values into the formula.

$d= 25 \ km/hr * 5 \ hr$

Multiply. The hours will cancel each other out.

$d= 125 \ km$

The bicyclist travels 125 kilometers.

mixas84 [53]2 years ago

6 0

Answer:

125 kilometers

Explanation:

Speed= 25km/h

Time = 5 h

Distance= Speed x Time

= 25 x 5

= 125 km

You might be interested in

Which of the following is true about a hybrid? * A. It combines the gas-powered engine and an electric motor into one system. B.

AleksAgata [21]

I'm pretty sure the answer is <u>A - It combines the gas-powered engine and an electric motor into one system.</u>

7 0

3 years ago

What is the gravitational potential energy of a two-particle system with masses 4.5 kg and 6.3 kg, if they are separated by 1.7

zepelin [54]

Answer:

7.41 x 10^-10 J

Explanation:

m = 4.5 kg

M = 6.3 kg

d = 1.7 m

The formula for the gravitational potential energy is given by

$U = \frac{-GMm}{d}$

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

$U = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{1.7}$

U = - 1.112 x 10^-9 J

Now the separation is tripled, d' = 3 x d = 3 x 1.7 m = 5.1 m

Let the potential energy is U'

The formula for the gravitational potential energy is given by

$U' = \frac{-GMm}{d'}$

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

$U' = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{5.1}$

U' = - 3.71 x 10^-10 J

the work done is equal to the change in potential energy

W = U' - U

W = - 3.71 x 10^-10 + 1.112 x 10^-9

W = 7.41 x 10^-10 J

7 0

3 years ago

two negative charge of -2.0 c and a positive charge of 3.0 c are separated by 80 m what is the force between two charges

kozerog [31]

The Coulomb force is equal to the constant k times the product of charge one and charge two over radius.

F=k((q1q2)/r)

6 0

3 years ago

Find the length of an arc with a radius of 6.0m swept across 2.5 radians.

soldier1979 [14.2K]

Hello!

In terms of an arc length, radians is the measurement of an arc length in terms of the original radius. This arc length is 2.5 radians, so we multiply it by our original radius.

2.5(6)=15

Therefore, the arc length is 15 meters.

I hope this helps!

7 0

3 years ago

The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou

Kipish [7]

Answer:

The excess charge on earth's surface was calculated to be 4.56 × 10⁵ C

Explanation:

Using the formula for an electric field;

E = kQ/r²

k = 1/(4πε₀) = 8.99 × 10⁹ Nm²/C²

E = 100N/C

r = radius of the earth = 6400 km = 6400000m

Q = Er²/k = 100 × (6400000)²/(8.99 × 10⁹)

Q = 455617.4 C = 4.56 × 10⁵ C

Hope this helps!!!

6 0

3 years ago