The nth term of an arithmetic sequence is found from:
Plugging in the given values, we get for the 13th term:
-58=14+12d
12d =-58 - 14 = -72
d = -6
So, the 32nd term is:
Answer:
1.99
Step-by-step explanation:
Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
The value of h(t) when 
is 10.02.
Solution:
Given function 
To find the value of h(t) when :
Substitute in the given function.
Now multiply the common terms into inside the bracket.
Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.
To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64
= 10.02
Hence the value of h(t) when is 10.02.
Answer:
11.82
Step-by-step explanation: I know this because 21.32-9.50= 11.82
