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melomori [17]
2 years ago
11

Answer two questions about Equations AAA and BBB: \begin{aligned} A.&&3(x+2)&=18 \\\\ B.&&x+2&=6 \end{al

igned} A. B. ​ ​ 3(x+2) x+2 ​ =18 =6 ​ 1) How can we get Equation BBB from Equation AAA? Choose 1 answer: Choose 1 answer: (Choice A) A Add/subtract the same quantity to/from both sides (Choice B) B Add/subtract a quantity to/from only one side (Choice C, Checked) C Multiply/divide both sides by the same non-zero constant (Choice D) D Multiply/divide only one side by a non-zero constant
Mathematics
2 answers:
pogonyaev2 years ago
5 0

Answer:

Multiply/divide both sides by the same non-zero constant

No

lukranit [14]2 years ago
3 0

Answer:

C Multiply/divide both sides by the same non-zero constant

Step-by-step explanation:

Given

A:\ 3(x + 2) = 18

B:\ x + 2 = 6

Required

How to get B from A

It can be seen that B is a factor of A.

And to get B from A, all you need to do is divide both sides of A by 3.

i.e.

\frac{3(x+2)}{3} = \frac{18}{3}

x+2 = 6

Hence, from the list of given options.

<em>Option C answers the question because 3 is a non zero constant and both sides of the equation were divided by 3</em>

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Gelneren [198K]

Answer:

General equation of line : y = mx+c   --1

Where m is the slope or unit rate

Table 1)

p    d

1      3

2     6

4     12

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

First find the slope

First calculate the slope of given points

m = \frac{y_2-y_1}{x_2-x_1}   ---A

(x_1,y_1)=(1,3)

(x_2,y_2)=(2,6)

Substitute values in A

m = \frac{6-3}{2-1}

m = 3

Thus the unit rate is 3 dollars per pound.

So, It matches the box 1 (Refer the attached figure)

Equation 1 : p=3d

\frac{p}{3}=d

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

m = \frac{1}{3}

Thus the unit rate is \frac{1}{3} dollars per pound

So, It matches the box 2 (Refer the attached figure)

Equation 2 : \frac{1}{3}d=3p

d=9p

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

m =9

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

Table 2)

p        d

1/9      1

1         9

2        18

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

(x_1,y_1)=(\frac{1}{9},1)

(x_2,y_2)=(1,9)

Substitute values in A

m = \frac{9-1}{1-\frac{1}{9}}

m = \frac{8}{frac{8}{9}}

m = 9

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

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