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jeyben [28]
3 years ago
5

Find the difference

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

-5n^2 +2n +5

Step-by-step explanation:

( -4n^2 +2n) - (n^2 -5)

Distribute the minus sign

( -4n^2 +2n) - n^2 +5

Combine like terms

-5n^2 +2n +5

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4. The sum of iwo numbers is 36. Twice the first
Ludmilka [50]

Answer:

  14 and 22

Step-by-step explanation:

If x is the first number, then 36-x is the second. We are told that ...

  2x -(36-x) = 6 . . . . twice the first less the second is 6

  3x = 42 . . . . . . . . . add 36

  x = 14

  (36 -x) = 22

The numbers are 14 and 22.

4 0
3 years ago
Help pls............!!!!!
mezya [45]

Answer:

The 3rd set

Step-by-step explanation:

The first set has a range of 6, not 5

The second set has a range of 5, but not a mean of 5

The third set has both a mean and a range of 5

8 0
3 years ago
Question 1 (Essay Worth 10 points)
Svetach [21]

Answer:

Because she is concluding that her class is an accurate representation of the overall school. The sample size in this case is too small and should increase her sample size(the amount of people surveyed) in order to get a better result.

8 0
3 years ago
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
3 years ago
Please help! i am confused
Brut [27]

Answer:

3

16+ x = 19

x= 3

Step-by-step explanation:

pls mark as brainliest ty

7 0
2 years ago
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