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3 years ago

choose a method then find the product 30 times 52

2 answers:

mihalych1998 [28]3 years ago

6 0

Put the 52 on top and then put the 30 on the bottom and hang the 0 so it looks like this 52
x 30

and then just put the zero down and multiply 52 times 3 and it is really easy to do!! theres also the turtle neck way but its really hard to explain!! hope this helped you!!!! :)

Lunna [17]3 years ago

5 0

First 3x52 = 156 then 156x10 = 1560

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2x + 7 =30, x = 3 true or false

RSB [31]

Answer:

False

Step-by-step explanation:

2x+7=30

2x=23

X= 23/2 or 11.5

X does not equal 3, therefore the statement is false

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3 years ago

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Find all zeros and write the answers in factored form (x-5)(3x^2-8x+6) =0

katen-ka-za [31]

Answer:

x-5=0

x=5

3x2-8x+6=0

d= 64 - 4*3*6= -8

x≠R

answer: only x=5

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3 years ago

Which of these debts could possibly be forgiven under Chapter 7 bankruptcy? A. Credit Card Debt B. Child Support C. Alimony D. A

a_sh-v [17]

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3 years ago

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21.60 divided by 1.35 is what?

klasskru [66]

Answer:

Step-by-step explanation:

21.60 divided by 1.35=16

8 0

3 years ago

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ccording to the U.S. National Weather Service, at any given moment of any day, approximately 1000 thunderstorms are occurring wo

viva [34]

Answer:

The critical value of z for 99% confidence interval is 2.5760.

The 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

Step-by-step explanation:

Let X = number of lightning strikes on each day.

A random sample of n = 23 days is selected to observe the number of lightning strikes on each day.

The random variable X has a sample mean of, $\bar x=8.1\ mn$ and the population standard deviation, $\sigma=0.51\ mn$ .

The (1 - α)% confidence interval for population mean μ is:

$CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Compute the critical value of z for 99% confidence interval is:

$z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.5760$

*Use a z-table.

The critical value of z for 99% confidence interval is 2.5760.

Compute the 99% confidence interval for population mean number of lightning strike as follows:

$CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\=8.1\pm2.5760\times\frac{0.51}{\sqrt{23}}\\=8.1\pm0.2738\\=(7.8262, 8.3738)\\\approx(7.83, 8.37)$

Thus, the 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

The 99% confidence interval for population mean number of lightning strike implies that the true mean number of lightning strikes lies in the interval (7.83 mn, 8.37 mn) with 0.99 probability.

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3 years ago