Question

binh is choosing from 6 youtube videos and and nine online role-playing games to link to his Myspace Page. If he randomly picks seven links total, find the probability that Binh chooses three YouTube videos and four online

Answer 1

Answer: $\frac{7}{450450}$

Step-by-step explanation:

Here, the number of you tube videos = 6,

The number of online role-playing games = 9,

⇒ Total number of games = 6 + 9 = 15,

Hence, the probability of choosing three you tube video and 4 online role playing games out of 7 chosen games,

$=\frac{^6C_{3}\times ^9C_{4}}{^15C_{7}}$

$=\frac{4\times 126}{32432400}$

$=\frac{504}{32432400}$

$=\frac{7}{450450}$

Answer 2

56/143
Using (6C3 x 9C4)/ 15C7 to find probability of 3 out of 6 youtube and 4 out of 6 online divided by  7 out of 15 total