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3 years ago

I NEED HELP PLEASE !!!!

Mathematics

1 answer:

Softa [21]3 years ago

4 0

Answer:

See below

Step-by-step explanation:

So we have the following six values:

$77.65488139\\\sqrt{0.156}\\368. 5468432...\\253,897,615.\bar3\\14.19274128...\\\\\sqrt{\frac{4}{9} }$

And we want to determine which are irrational.

Recall what irrational numbers, are they are numbers that do not<em> </em>repeat nor terminate. In other words, they never end, and their digits never repeat.

So, let's go through each one.

77.65488139 is rational. Yes, it has a lot of decimal places but notice there are no ellipses after it. Thus, it terminates and is rational.

√(0.156) is about (use a calculator) 0.39496835... It is not repeating nor does it end. Thus, √(0.156) is irrational.

368.5468432... has the ellipses. Thus, it doesn't repeat and doesn't terminate. It's irrational.

253,897,615.3 has a bar over the 3 at the end. This means that this repeats. Therefore, while it doesn't terminate, it is rational.

14.19274128... has an ellipses. It doesn't repeat nor terminate. It's irrational.

Lastly, the square root can be simplified to 2/3. This is approximately .6666... While this doesn't terminate, it repeats, so it's rational.

Edit: Grammar

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1 year ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

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scoray [572]

Let me express the equation clearly:

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Initially, we solve this by substituting x=-9 to the equation.

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Answer:

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Hence his body temperature in the evening is 102.6°F.

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