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3 years ago

I NEED HELP PLEASE !!!!

Mathematics

1 answer:

Softa [21]3 years ago

4 0

Answer:

See below

Step-by-step explanation:

So we have the following six values:

$77.65488139\\\sqrt{0.156}\\368. 5468432...\\253,897,615.\bar3\\14.19274128...\\\\\sqrt{\frac{4}{9} }$

And we want to determine which are irrational.

Recall what irrational numbers, are they are numbers that do not<em> </em>repeat nor terminate. In other words, they never end, and their digits never repeat.

So, let's go through each one.

77.65488139 is rational. Yes, it has a lot of decimal places but notice there are no ellipses after it. Thus, it terminates and is rational.

√(0.156) is about (use a calculator) 0.39496835... It is not repeating nor does it end. Thus, √(0.156) is irrational.

368.5468432... has the ellipses. Thus, it doesn't repeat and doesn't terminate. It's irrational.

253,897,615.3 has a bar over the 3 at the end. This means that this repeats. Therefore, while it doesn't terminate, it is rational.

14.19274128... has an ellipses. It doesn't repeat nor terminate. It's irrational.

Lastly, the square root can be simplified to 2/3. This is approximately .6666... While this doesn't terminate, it repeats, so it's rational.

Edit: Grammar

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The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c

Slav-nsk [51]

$\text{Answer} : \text{The expected value of a t-shirt is \$31.}$

Explanation:

Since we have given that

The prices of three t-shirts styles i.e $24, $30, $36 with their probability is given by

$\frac{1}{6}, \frac{1}{2},\frac{1}{3}$

As we know that,

$E(X)= \sum_{1}^{3}x_iP(x_i)$

$\text{where} x_i \text{ is the prices of t- shirts styles}$

Now,

$x_1= \$24 , x_2=\$30 , x_3=$36$

and

$P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}$

So,

$E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31$

So, the expected value of a t-shirt = $31.

4 0

3 years ago

What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?

posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

$\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\$