Answer:
10,014,070
Step-by-step explanation:
Answer:

Step-by-step explanation:
Consider right triangle ABC with right angle C.
In this triangle,
- BA = 9.8 in
- CB = 6.3 in
- CA = 7.5 in
Write trigonometric functions:

Hence,

Answer:
The Trout will have to jump 49 cm in order to catch the insect
Step-by-step explanation:
Here, we want to calculate the distance the Trout has to jump in order to catch the Insect
To calculate this, we need to know the difference in the distances
From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake
The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;
17 + 32 = 49 cm
Answer:
Step-by-step explanation:
cos theta is 2/3 because cos means reciprocal of sec
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π and cos A = cos B · cos C
scratchwork:
A + B + C = π
A = π - (B + C)
cos A = cos [π - (B + C)] Apply cos
= - cos (B + C) Simplify
= -(cos B · cos C - sin B · sin C) Sum Identity
= sin B · sin C - cos B · cos C Simplify
cos B · cos C = sin B · sin C - cos B · cos C Substitution
2cos B · cos C = sin B · sin C Addition
Division
2 = tan B · tan C

<u>Proof LHS → RHS</u>
Given: A + B + C = π
Subtraction: A = π - (B + C)
Apply tan: tan A = tan(π - (B + C))
Simplify: = - tan (B + C)

Substitution: = -(tan B + tan C)/(1 - 2)
Simplify: = -(tan B + tan C)/-1
= tan B + tan C
LHS = RHS: tan B + tan C = tan B + tan C 