Question

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Answer 1

Answer:x2_>16 B.

Step-by-step explanation:

Answer 2

For this case we will show that the correct option is option C.

$x ^ 2 \leq16$

We find the value of the variable "x":

We apply root to both sides of the equation to eliminate the exponent:

$x \leq \pm \sqrt {16}\\x \leq \pm4$

We found the first solution with the positive value:

$x \leq4$

We use the negative value to find the other solution. Since it is an inequality, the sign of the inequality changes in the negative portion of the solution.

$x \geq-4$

So, the roots are:

$x_ {1} \geq-4\\x_ {2} \leq + 4$

The solution is given by the values of "x" greater than or equal to -4 and less than or equal to 4

Answer:

Option C