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3 years ago

Please answer photo below thank you :’)

Mathematics

2 answers:

Sloan [31]3 years ago

7 0

Answer:x2_>16 B.

Step-by-step explanation:

KatRina [158]3 years ago

7 0

For this case we will show that the correct option is option C.

$x ^ 2 \leq16$

We find the value of the variable "x":

We apply root to both sides of the equation to eliminate the exponent:

$x \leq \pm \sqrt {16}\\x \leq \pm4$

We found the first solution with the positive value:

$x \leq4$

We use the negative value to find the other solution. Since it is an inequality, the sign of the inequality changes in the negative portion of the solution.

$x \geq-4$

So, the roots are:

$x_ {1} \geq-4\\x_ {2} \leq + 4$

The solution is given by the values of "x" greater than or equal to -4 and less than or equal to 4

Answer:

Option C

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Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r

Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

$\mu=\$1000\\\sigma=\$370\\n=80$

As n = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let $\bar X$ represent the sample mean weekly salaries.

The distribution of $\bar X$ is: $\bar X\sim N(\$1000,\ \$41.37)$

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, $|\bar X-\mu|= 75$ .

Compute the probability as follows:

$P(-75$

$=P(-1.81$

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

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3 years ago

Which equation best represents the relationship between x and y ?

Butoxors [25]

Y=25x

i hope this is what you’re asking for

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2 years ago

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