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Solnce55 [7]
3 years ago
14

Solve by completing the square -x^2+8x-6=0

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0
-x² + 8x - 6 = 0
x = <u>-(8) +/- √((8)² - 4(-1)(-6))</u>
                     2(-1)
x = <u>-8 +/- √(64 - 20)</u>
                 -2
x = <u>-8 +/- √(44)
</u>              -2<u>
</u>x = <u>-8 +/- 2√(11)
</u>              -2
x = <u>-8 + 2√(11)</u>         x = <u>-8 - 2√(11)
</u>             -2                            -2<u>
</u>x = 4 - √(11)             x = -8 + √(11)
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Answer:

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Explanation:

We have been given with the quadratic equation x^2-7x-6=0

We have general formula to find the roots of a quadratic equation first we find the discriminant with formula

D=b^{2}-4ac

and after that to find the variable suppose x we have the formula

x=\frac{-b\pm\sqrt{D}} {2a}

And general quadratic equation is

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On comparing the given quadratic equation with genral quadratic equation we will have values

a=1, b=-7 and c=-6

After substituting these values in the formula we will get  

D=(-7)^2-4(1)(-6)={73}

After substituting in the formula to find x we will get

\frac{-(-7)\pm\sqrt{73}} {2}= \frac{7\pm\sqrt{73}} {2}

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