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Solnce55 [7]
3 years ago
14

Solve by completing the square -x^2+8x-6=0

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0
-x² + 8x - 6 = 0
x = <u>-(8) +/- √((8)² - 4(-1)(-6))</u>
                     2(-1)
x = <u>-8 +/- √(64 - 20)</u>
                 -2
x = <u>-8 +/- √(44)
</u>              -2<u>
</u>x = <u>-8 +/- 2√(11)
</u>              -2
x = <u>-8 + 2√(11)</u>         x = <u>-8 - 2√(11)
</u>             -2                            -2<u>
</u>x = 4 - √(11)             x = -8 + √(11)
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Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x
Savatey [412]
The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

\dfrac{2x^3+14x^2-58x}{x+10}

You have

..... | 2 ...  14  ... -58
-10 |    ... -20  ... 60
--------------------------
..... | 2 ...  -6  ....  2

So the quotient and remainder upon dividing is

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vredina [299]
We are tasked to solve the value of p(8a) in the expression p(x)=3x^2-4.
This means that what would find the value of the expression when x=8a. To solve this, we simply substitute the value of x in the expression.

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