Using the normal distribution, there is a 0.1894 = 18.94% probability that the sample average will exceed $75.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
The parameters for this problem are given as follows:

The probability that the sample average will exceed $75 is <u>one subtracted by the p-value of Z when X = 75,</u> hence:

By the Central Limit Theorem

Z = (75 - 70)/5.66
Z = 0.88
Z = 0.88 has a p-value of 0.8106.
1 - 0.8106 = 0.1894.
0.1894 = 18.94% probability that the sample average will exceed $75.
More can be learned about the normal distribution at brainly.com/question/28096232
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Answer:
(x - 6) • (4x - y)
Step-by-step explanation:
brainly???
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(4x • (x - 6)) - y • (x - 6)
Step 2 :
Equation at the end of step 2 :
4x • (x - 6) - y • (x - 6)
Step 3 :
Pulling out like terms :
3.1 Pull out x-6
After pulling out, we are left with :
(x-6) • ( 4x * 1 +( y * (-1) ))
Final result :
(x - 6) • (4x - y)
All real numbers are solutions, let me know if you need an explanation luv
Answer:
a) The car will be worth $8000 after 2.9 years.
b) The car will be worth $6000 after 4.2 years.
c) The car will be worth $1000 after 12.7 years.
Step-by-step explanation:
The value of the car after t years is given by:

According to the model, when will the car be worth V(t)?
We have to find t for the given value of V(t). So





(a) $8000
V(t) = 8000

The car will be worth $8000 after 2.9 years.
(b) $6000
V(t) = 6000

The car will be worth $6000 after 4.2 years.
(c) $1000
V(t) = 1000

The car will be worth $1000 after 12.7 years.
First deducte his contribution
7,058−7,058×0.70
=2,117.4
Then find weekly deduction
2,117.4÷52
=40.72