Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.
So we can use formula of perimeter of rectangel to find it's possible dimensions.
We knwo that perimeter of the rectangle is given by 2(L+W)
where L is lenght and W is width.
Given perimeter is 20 so we get:
2(L+W)=20
L+W=10
L=10-W
So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.
Let W=4
Then L=10-W=10-4=6
Hence we just have to draw a rectangle having length 6 and width 4.
So the final answer will be picture in the attached graph.
Answer:
Polinomios irreducibles (primos) Un polinomio con coeficientes enteros que no pueden ser factorizados en polinomios de grado menor, también con coeficientes enteros, es llamado un polinomio irreducible o primo
Step-by-step explanation:
A)she is not right.because if the remaining peice is the hypotenuse of the triangle, the answer will be around 27.8 if the hypotenuse is 22 then the missing angle is 13.96
b)yes it will work
if you double the measurements of the two sides of a right triangle the other one will be double, too(you can get help from Pythagoras theorem )
c)yes it is possible. if we can double the sides of a right triangle it means that we add measurements to the triangle.
for example:a triangle with sides of 3,4,5
if we add 6,8,10
it will be 9,12,15
hope I could help
