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Natali5045456 [20]
3 years ago
12

3. Put the following numbers in order

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

Answer:

-7, -6, -5, 0.00000538, 3.58, 3.85, 8.53, 10, 10, 10

Step-by-step explanation:

-7, -6, -5, 0.00000538, 3.58, 3.85, 8.53, 10, 10, 10

-7, -6, -5, 0.00000538, 3.58, 3.85, 8.53, 10, 10, 10

PtichkaEL [24]3 years ago
5 0

Answer:

3.85 x 10-7

8.53 x 10-5

0.00000538

3.58 x 10-6

Step-by-step explanation:

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2 years ago
what is the value of x in the diagram below? if necessary round your answer to the nearest tenth of a until
VladimirAG [237]

Answer:

C

Step-by-step explanation:

Calculate AC using Pythagoras' identity in ΔABC

AC² = 20² - 12² = 400 - 144 = 256, hence

AC = \sqrt{256} = 16

Now find AD² from ΔACD and ΔABD

ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²

ΔABD → AD² = 12² - x² = 144 - x²

Equate both equations for AD², hence

256 - 400 + 40x - x² = 144 - x²

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40x = 288 ( divide both sides by 40 )

x = 7.2 → C



6 0
2 years ago
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90. The number of daily evening newspapers in the United States has decreased by 46.5% to
aleksandr82 [10.1K]

Answer:

700

Step-by-step explanation:

Given:

Daily evening newspapers in 2015 = 389

Percentage decrease from 2000 to 2015 = 46.5%

To find:

Number of newspapers in 2000 = ?

Solution:

Let the number of newspapers in 2000 = x

When 46.5% of the total newspapers in 2000 (x) is subtracted from the total  newspapers in 2000 (x), it will be equal to the number of newspapers in 2015.

Making the equation as per the given statement:

x-x\times 46.5\%=389\\\Rightarrow \dfrac{100x-46.5x}{100}=389\\\Rightarrow 53.5x=38900\\\Rightarrow x\approx \bold{727}

Therefore, the answer is:

There were <em>727 </em>newspapers in 2000.

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