Answer:
-7, -6, -5, 0.00000538, 3.58, 3.85, 8.53, 10, 10, 10
Step-by-step explanation:
3.85 x 10-7
8.53 x 10-5
0.00000538
3.58 x 10-6
C
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = = 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
700
Given:
Daily evening newspapers in 2015 = 389
Percentage decrease from 2000 to 2015 = 46.5%
To find:
Number of newspapers in 2000 = ?
Solution:
Let the number of newspapers in 2000 =
When 46.5% of the total newspapers in 2000 () is subtracted from the total newspapers in 2000 (), it will be equal to the number of newspapers in 2015.
Making the equation as per the given statement:
Therefore, the answer is:
There were <em>727 </em>newspapers in 2000.
Answer: the sky and planets
the are above us