How many seconds are in a 19 years?

Catherine and Lance open a savings account at the same time. Catherine deposits $100 initially and adds $20 per week. Lance depo

docker41 [41]

Answer:

After 40 weeks

Step-by-step explanation:

To get the answer to this question, we need to first know the difference in the amount of money deposited by the 2 individuals and in this case it us $400 since one deposited $500 and the other $100

The next thing to do is to divide the difference in amount(400) by the amount contributed by each person per week.

Catherine deposits $20 per week

400/20 = 20

Lance deposits $10 per week

400/10 = 40

The LCM between 40 and 20 is 40 weeks.

Therefore, both individuals need to deposit money for 40 weeks for both of their savings to be the same.

If Catherine deposits $20 for 40 weeks,she will have 40 × 20 = $800 + $100(initial deposit that she made) = $900

Lance deposits $10 for for 40 weeks and he will have 40 × 10 = $400 + $500(initial deposit made by him)= $900

4 0

3 years ago

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Hi there can anyone help me with this question please

levacccp [35]

The answer is 4. The mean is 4 beacuse thats what you multiply ... and yeah

4 0

3 years ago

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Which pairs of points would result in a line with a rate of change of 2:1? select all that apply

Reil [10]

Answer:

A,C,D

Step-by-step explanation:

Complete Question:

"Which pairs of points would result in a line with a rate of change of 2:1? select all that apply"

A.(−4,−11) and (−2−7)

B.(5,6) and (−5, 12)

C.(0,−3)and (−4,−11)

D. (0,−3) and (5, 7)

Rate of change is the slope. 2:1 would mean a slope of simply, 2.

We need to find slope of each of the choices from A - D and see which one has 2. The formula would be:

$m=\frac{y_2-y_1}{x_2-x_1}$

Where m is the slope and

x_1 is first x point

x_2 is second x point

y_1 is first y point

y_2 is second y point

Let's calculate slope of each of the choices.

A.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-7+11}{-2+4}\\m=2$

THis one is okay.

B.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{12-6}{-5-5}\\m=-\frac{3}{5}$

THis one is not 2:1.

C.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-11+3}{-4-0}\\m=2$

THis one is okay.

D.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{7+3}{5-0}\\m=2$

This one is okay.

Hence, A, C, and D all have rate of change of 2:1

4 0

3 years ago

The figure shows how a leaf meets the stem of a flower to form two angles. basically find x

DochEvi [55]

Answer:

-72

Step-by-step explanation:

6 0

2 years ago

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: Find the approximate perimeter of the isosceles triangle A OPD.

AleksAgata [21]

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

$P=OP+PD+OD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

$d=\sqrt{(-6+6)^{2}+(1-7)^{2}}$

$d=\sqrt{(0)^{2}+(-6)^{2}}$

$d_O_P=6\ units$

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-1)^{2}}$

$d=\sqrt{(9)^{2}+(3)^{2}}$

$d_P_D=\sqrt{90}\ units$

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-7)^{2}}$

$d=\sqrt{(9)^{2}+(-3)^{2}}$

$d_O_D=\sqrt{90}\ units$

step 4

Find the perimeter

$P=6+\sqrt{90}+\sqrt{90}$

$P=6+9.49+9.49=24.98\ units$

4 0

3 years ago