1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
spin [16.1K]
3 years ago
13

Solve x2-14x+21=0 by completing the square

Mathematics
1 answer:
ankoles [38]3 years ago
4 0
x^2-14x+21=0\\\\x^2-2x\cdot7+7^2-7^2+21=0\\\\(x-7)^2-49+21=0\\\\(x-7)^2-28=0\\\\(x-7)^2=28\iff x-7=-\sqrt{28}\ \vee\ x-7=\sqrt{28}\\\\x=7-\sqrt{4\cdot7}\ \vee\ x=7+\sqrt{4\cdot7}\\\\x=7-2\sqrt7\ \vee\ x=7+2\sqrt7
You might be interested in
Micah made a scale model of the Empire State building.The building has an actual height of 381 meters. Micah’s model used a scal
Marysya12 [62]

<em>Answer:</em>

<em>1cm = 50 </em>

<em>2 cm = 50 x 2 </em>

<em>3cm = 50 x 3 </em>

<em>and the inverse:50m = 50/50 = 1cm </em>

<em>100m = 100/50 = 2cm </em>

<em>150m = 150/50 = 3cm </em>

<em>381m = 381/ </em>

3 0
3 years ago
(05.01)Which equation can be used to calculate the area of the shaded triangle in the figure below?
Lemur [1.5K]
2nd one, take area of whole 12 x 4=48, if area is equally divided, divide area by 2 or multiply by 1/2

7 0
3 years ago
Read 2 more answers
Suppose the probability of producing a defective light bulb from a production line is the same over an interval of 90 minutes. W
butalik [34]

Answer:

C) Uniform distribution

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely. In this case, the probability of producing a defective light bulb from a production line is the same over an interval of 90 minutes, so the correct answer is C.

We can calculate the probability.

Uniform probability distribution

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

Uniformily distributed over a 90 minute interval, that is, between 0 and 90, so b = 90 and a = 0.

We want to find P(X \leq 15) = \frac{15-0}{90-0} = 0.167

8 0
3 years ago
3(4+2)=30<br> pls help me
vladimir1956 [14]

Answer:

Isn't it 18?

Step-by-step explanation:

Because you need to add 4 and 2 then multiply it with 3?

5 0
3 years ago
In a group of 25 students, 6 study both Art and Biology. 10 study Biology but not Art. 3 study neither subject. Given that a ran
olga2289 [7]

Answer:

1/2

Step-by-step explanation:

There are a total of 25 students. 3 don't study art or biology. 10 study only biology. 6 study both art and biology. This means the remaining students only study art.

1. Calculate the number of students taking art

only art: 25 - 3 - 6 - 10 = 6

number of students taking art and biology: 6

total number of students taking art: 12

2. Calculate the probability

Out of the 12 total students taking art, 6 are in art and biology.

6/12 = 1/2  

6 0
3 years ago
Other questions:
  • What number is multiplied to -1 and then adds to -5
    8·1 answer
  • What is 9 as a fraction with 6 as a denominator
    9·1 answer
  • If f(x) = -2x – 3 and g(x) = x2 – 1 find f(-3) + g(3).
    12·1 answer
  • 1. What equation is modeled with the following number line? A. 7 – 3 = 4 B. 4 + 3 = 7 C. 3 + 4 = 7 D. 7 – 4 = 3
    12·2 answers
  • Pls Can we be friends
    9·2 answers
  • Which of the binomials below is a factor of this
    7·2 answers
  • A sporting goods store has a sale on soccer balls: if you buy two soccer balls at the regular price, you get a third soccer ball
    10·1 answer
  • According to Thomson Financial, last year the majority of companies reporting profits had beaten estimates. A sample of 162 comp
    14·1 answer
  • Over a 5-hour period, the
    10·1 answer
  • There are 12 girls and 16 boys . What is the largest number in each group?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!