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77julia77 [94]
3 years ago
15

When a particle is located a distance x meters from the origin, a force of cos(πx/7) newtons acts on it. Find the work done in m

oving the particle from x=3 to x=3.5. equation editorEquation Editor Find the work done in moving the particle from x=3.5 to x=4. equation editorEquation Editor Find the work done in moving the particle from x=3 to x=4.
Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

Badass means

Step-by-step explanation:

Bogdanich family

Ros77e up lol

Princess Diana style

Change someones life

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Factor 8c + 10c?.<br> ✅p
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Which of the following is equivalent to 5^-9
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0.0000000005 9 zeros
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write an equation you could use to find the length of the missing side of each triangle. Then find the missing length. Round to
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A membership to the gym costs $25 per person in 1995. The membership cost has increased by an average of $6 per person for each
inysia [295]

Answer:

The cost of a gym membership would be 109

Step-by-step explanation:

2009-1995=14

thats how many years apart from each other

so its been 14 years $6 for each year so 14x6=84

so the regular price was $25 and went up 84 dollars last 14 years.

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6 0
3 years ago
A company is making a new label for one of their containers. The container is a cylinder that is 9 inches tall and 5 inches in d
nydimaria [60]

Answer:

180.55 in².

Step-by-step explanation:

Data obtained from the question include the following:

Height (h) = 9 in.

Diameter (d) = 5 in

Pi (π) = 3.14

Area of the label =..?

Next, we shall determine the radius.

Diameter (d) = 5 in

Radius (r) =.. ?

Radius (r) = Diameter (d) /2

r = d/2

r = 5/2

r = 2.5 in.

Next, we shall determine the area of the label that needs to be printed to go around the new container by calculating the surface area of the cylinder.

This is illustrated below:

Height (h) = 9 in.

Pi (π) = 3.14

Radius (r) = 2.5 in.

Surface Area (SA) =.?

SA = 2πrh + 2πr²

SA = (2×3.14×2.5×9) + (2×3.14×2.5²)

SA = 141.3 + 39.25

SA = 180.55 in²

The surface area of the cylinder is 180.55 in².

Therefore, the area of the label that needs to be printed to go around the new container is 180.55 in².

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3 years ago
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