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2 years ago

PLEASE ANSWER QUICK!!! Identify the equation of the circle that has its center at (-8, 15) and passes through the origin.

Mathematics

2 answers:

valentinak56 [21]2 years ago

6 0

(X+8)^2+(y-15)^2=289 would be the equation to the circle

Ann [662]2 years ago

6 0

(x + 8)^2 + (y - 15)^2 = 17^2

Equation of a circle
Midpoint at (a,b)

(x - a)^2 + (y - b)^2 = r^2

You know what the circle’s center is so you can substitute those values in

(x + 8)^2 + (y - 15)^2 = r^2

But you don’t know what the radius is. To find the radius, we know that the circle passes through the origin (0,0) so you just use the distance formula to figure out the radius length.

Distance formula:

Square root of (x1 - x2)^2 + (y1 - y2)^2

So...

Square root of (-8 - 0)^2 + (15 - 0)^2
Square root of 64 + 225
Square root of 289
r=17

So you substitute 17 into the equation of a circle formula and the result is:

(x + 8)^2 + (y - 15)^2 = 17^2

~~hope this helps~~

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2 years ago

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3 years ago

Read 2 more answers

The observations of 124.53, 124.55, 142.51, and 124.52 are obtained when taping the length of a line. What should the observer c

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As it can be easily seen, the third measure is much different from the other three. This means that something went wrong during the observation: it can be either the measure taken wrong or that the number was written wrong (if you switch the 2 and the 4 you get a number similar to the other ones).

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2 years ago

The population of the town increased from 175000 to 262500 in a decade. What is the average percent increase of population per y

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Answer:

Step-by-step explanation:

As given,

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