Answer:
when the radius is halved, F becomes 4 times
Explanation:
<u><em>The formula is given by</em></u>
<u><em>When r is halved:</em></u>
=>
=>
<u><em>This means when the radius is halved, F becomes 4 times</em></u>
Answer:
x = 2.37 cm
Explanation:
given,
density of oil = 923 kg/m³
height of the block = 4.81 cm
density of the block = 961 Kg/m³
density of water = 1000 Kg/m³
Let x be the depth of the block in the water.
now,
Weight of block will be acting downward.
Buoyancy force will be acting on the block because of the oil and water.
At equilibrium position both weight and the buoyant force will balance.
x = 0.0237 m
x = 2.37 cm
Hence, the block is 2.37 cm in the water.
It would be "Double replacement".
Hope this helps!
Answer:
tension in the rope is 22.29 N
angle is 56.06 degree
Explanation:
Given data
mass = 1.27 kg
horizontal force = 18.5 N
acceleration = 9.81 m/s2
to find out
magnitude and the rope angle
solution
we know object is in equilibrium so net force is zero here
so net force at x axis = 0 that mean F - Tsinθ = 0 , F = Tsinθ
and net force at y axis = 0 that is T cosθ - mg = 0 , T cosθ = mg
in equilibrium condition
F / mg = Tsinθ / T cosθ
18.5/ 1.27× 9.81 = sinθ / cosθ
so θ = tan^-1 (1.4859)
θ = 56.06 degree
angle is 56.06 degree
so F = Tsinθ
18.5 = T sin(56.06)
T = 18.5 / 0.8296
tension in the rope is 22.29 N
Answer:
Explanation:
Suppose mass of block 1 is and of block 2
For original system
natural frequency of oscillation is given by
Maximum kinetic Energy is equal to total Energy of the system
where k=spring constant
A=maximum amplitude
Now Block B is Placed at block 1 at maximum amplitude such that A=A'
i.e. new amplitude=old amplitude
Maximum kinetic energy of combined system is
as the total energy is independent of mass therefore maximum kinetic energy will remain same