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4 years ago

If a tree of 5.5 meters casts a shadow of 3 meters. How high will a tower that gives a shadow of 15 meters be?

Physics

1 answer:

n200080 [17]4 years ago

3 0

Answer:

The height of a tower would be 27.5 meters

Explanation:

Notice that in both cases you are dealing with diagrams representing vertical objects and shadows created by the sun, against the ground, so we are in the presence of right angle triangles which have in common another angle (that made by the rays of the sun. So we can use similar triangles and the proportion that is generated based on the quotient of similar sides to find the unknown height (h).

$\frac{5.5}{3} =\frac{h}{15} \\h=\frac{(5.5)\,(15)}{3} \\h=27.5\,\,m$

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You weigh 716 newtons on Earth. You

Otrada [13]

Answer:

537 N

Explanation:

The force due to gravity of a planet is:

F = GMm / r²

where G is the universal gravitational constant

M is the mass of the planet

m is the mass of the object

and r is the distance between the object and the center of the planet

On Earth, you weigh 716 N, so:

716 N = GMm / r²

On planet X:

F = G (3M) m / (2r)²

F = 3/4 GMm / r²

F = 3/4 (716 N)

F = 537 N

8 0

4 years ago

What do you think happens to kinetic energy with potential energy being increased?

swat32

Answer:

If the kinetic energy increases, the potential energy decreases, and vice-versa.

Explanation:

The amount of change in kinetic energy is equal to the amount of change in potential energy.

8 0

2 years ago

4. T or F X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves.

Anna [14]

4. The X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves is a False.

5. The amplitude of water waves as you get farther from the disturbance that caused them decreases.

<h3>What is electromagnetic spectrum?</h3>

The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.

They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.

4. The Earth's environment is thick an adequate number of that for all intents and purposes no X-beams can come through from space the entire way to the Earth's surface. This is great as far as we're concerned yet in addition terrible for stargazing. We need to put X-beam telescopes and identifiers on satellites.

Thus, X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of wave is a False statement.

5. The amplitude of the wave decreases as the time period increases. But when we get far from the disturbance, the amplitude increases.

Thus, the amplitude of water wave increases as we get farther from the disturbance.

Learn more about electromagnetic spectrum.

brainly.com/question/23727978

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3 0

2 years ago

A warehouse worker is pushing a 90.0-kg crate with a horizontal force of 282 N at a speed of v = 0.850 m/s across the warehouse

Elanso [62]

Answer:

$v_{f} = 0.51 \frac{m}{s}$

Explanation:

We apply Newton's second law at the crate :

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Data:

m=90kg : crate mass

F= 282 N

μk =0.351 :coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Crate weight (W)

W= m*g

W= 90kg*9.8 m/s²

W= 882 N

Friction force : Ff

Ff= μk*N Formula (2)

μk: coefficient of kinetic friction

N : Normal force (N)

Problem development

We apply the formula (1)

∑Fy = m*ay , ay=0

N-W = 0

N = W

N = 882 N

We replace the data in the formula (2)

Ff= μk*N = 0.351* 882 N

Ff= 309.58 N

We apply the formula (1) in x direction:

∑Fx = m*ax , ax=0

282 N - 309.58 N = 90*a

a= (282 N - 309.58 N ) / (90)

a= - 0.306 m/s²

Kinematics of the crate

Because the crate moves with uniformly accelerated movement we apply the following formula :

vf²=v₀²+2*a*d Formula (3)

Where:

d:displacement in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

Data

v₀ = 0.850 m/s

d = 0.75 m

a= - 0.306 m/s²

We replace the data in the formula (3)

vf²=(0.850)²+(2)( - 0.306 )(0.75 )

$v_{f} = \sqrt{(0.850)^{2} +(2)( - 0.306 )(0.75 )}$

$v_{f} = 0.51 \frac{m}{s}$

8 0

3 years ago

a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel d

trasher [3.6K]

50π m ≈ 157 m
Explanation:
100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s
d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m

8 0

3 years ago