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Sever21 [200]
3 years ago
13

a hammer is dropped on the moon. it reaches the ground 5 seconds later. if the distance it fell was 5 meters, calculate the acce

leration to gravity on the moon
Physics
1 answer:
Artyom0805 [142]3 years ago
8 0
It is one meters per second
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RP 1 - Specific Heat Capacity GCSE Exam Questions (B.S.G)
Stels [109]

When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.

A sample of 0.50 kg of water boils (reaches 100 °C). After a while, its temperature decreases by 22 °C.

We can calculate the energy transferred to the surroundings from the water in the form of heat (Q) using the following expression.

Q = c \times m \times \Delta T = \frac{4200J}{kg.\° C}  \times 0.50kg \times (-22\° C) \times \frac{1kJ}{1000J} = -46.2 kJ

where,

  • c: specific heat capacity of water
  • m: mass of water
  • ΔT: change in the temperature

When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.

Learn more: brainly.com/question/16104165

8 0
2 years ago
The most common form of angina is _______ angina. A. microvascular B. variant C. stable D. unstable
Paraphin [41]

The most common form of angina is stable angina.

C. stable

8 0
2 years ago
Read 2 more answers
What is the final speed of a lion initially running at a speed of 30 m/s, if it accelerates at
cricket20 [7]
The final speed of a lion running 30 m/s accelerates at a rate of 3 m/s3 for 5 seconds it’s 3.2
8 0
3 years ago
How many total electrons are there in a water molecule<br><br>4<br>10<br>2
andre [41]
10 electrons are in a water molecule. :)
3 0
3 years ago
What ramp angle would produce an acceleration of 2 m/s2 for a cart rolling down? Assume no friction and that the angle is measur
r-ruslan [8.4K]
From Newton's second law:
a = F/mass
Therefore, acceleration of an object rolling a ramp would be:
a = g(sin theta) - friction coefficient (g) (sin theta)
The negative sine is due to the kinetic energy opposing the gravity

We are given that the friction coefficient is zero, the g is a constant = 9.8 m/sec and the acceleration is 2 m/sec^2
Substituting in the equation, we get:
2 = 9.8 sin(theta)
sin (theta) = 0.20408
theta = 11.7757 degrees 
7 0
3 years ago
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