When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.
A sample of 0.50 kg of water boils (reaches 100 °C). After a while, its temperature decreases by 22 °C.
We can calculate the energy transferred to the surroundings from the water in the form of heat (Q) using the following expression.

where,
- c: specific heat capacity of water
- m: mass of water
- ΔT: change in the temperature
When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.
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10 electrons are in a water molecule. :)
From Newton's second law:
a = F/mass
Therefore, acceleration of an object rolling a ramp would be:
a = g(sin theta) - friction coefficient (g) (sin theta)
The negative sine is due to the kinetic energy opposing the gravity
We are given that the friction coefficient is zero, the g is a constant = 9.8 m/sec and the acceleration is 2 m/sec^2
Substituting in the equation, we get:
2 = 9.8 sin(theta)
sin (theta) = 0.20408
theta = 11.7757 degrees