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3 years ago

Give an example of a system that has no solutions

Mathematics

1 answer:

Anna11 [10]3 years ago

5 0

Answer:

|3+x|=-3

Step-by-step explanation:

This equation has no solution because the answer would be - x=-3 X can't be negative 3 because if we inputed -3 into the absolute value, it wouldn't make any sense, as the absolute value of -3 is +3

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(Tough day dividing polynomials and I'm still lost!) Please help me my hands are legit numb:)

N76 [4]

Answer:

Option D. 9

Step-by-step explanation:

There are two ways to obtain the answer to the question.

Method 1:

Let 2x + 1 = 0

Making x the subject, we have

2x + 1 = 0

Collect like terms

2x = –1

Divide both side by 2

x = –1/2

Now, put the value of x into the expression 4x³ – 6x² – 8x + 7, we have:

4x³ – 6x² – 8x + 7

x = –1/2

4(–1/2)³ – 6(–1/2)² – 8(–1/2) + 7

4(–1/8) – 6(1/4) – 8(–1/2) + 7

–1/2 – 3/2 + 4 +7

– 4/2 + 4 + 7

– 2 + 4 + 7

= 9

Method 2:

Divide 4x³ – 6x² – 8x + 7 by 2x + 1

Please see attached photo for explanation.

4 0

4 years ago

Are these lines perpendicular?<br> yes<br> no

liberstina [14]

Answer:

Step-by-step explanation:

perpendicular means that they intersect at a 90° angle

4 0

2 years ago

The vertices of angleABC are A(1,1) B(5,1) C(3,3) drawl the triangle and it’s image A’B’C’ reflected in the Y axis. What are the

nevsk [136]

For any point reflected in the y- axis

(x, y ) → (- x, y )

A(1, 1) → A'(- 1, 1)

B(5, 1 ) → B'(- 5, 1 )

C(3, 3 ) → C'(- 3, 3 )

6 0

3 years ago

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

4 years ago

A triangles inside angles all add up to how many degrees

Inessa [10]

Answer:

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8 0

3 years ago

Read 2 more answers