How many 34-centimeter cubes do you need to create a cube with an edge length of 12 centimeters?

Mathematics

1 answer:

miskamm [114]3 years ago

8 0

You will only need 2.83% of the 34 cm cube

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Which angle has a sine of -1/2 and a cosine of -√3/2

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$\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}$

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If it is $\frac{3}{3(4c+16)}$ =2c+9, go to AAAAAA
if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, go to BBBBB

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$\frac{3}{3(4c+16)}$ =2c+9
$\frac{1}{4c+16}$ =2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
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BBBBBBBBBBBB
(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5

if it is $\frac{3}{3(4c+16)}$ =2c+9,
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, c=-3.5

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Step-by-step explanation:

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