All categories

3 years ago

The graph represents this piecewise function

Mathematics

2 answers:

IrinaK [193]3 years ago

6 0

Top one is x+3, bottom one is 5

Dominik [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Given is a piecewise graph.

From the graph we find that the domain is [-3,1]

From [-3,-1) the line is slant passing through (-3,0)(-2,1)

Slope =change in y/change in x = 1

Equation is y = x+3

Thus the function is x+3 for -3≤x<-1

and 5, -1≤x≤1

You might be interested in

The expression 14.50x can be used to find the total cost for x tickets on Family Night for admission and the movie. What is the

sp2606 [1]

All you have to do is substitute x for 3.
You get:
14.50 times 3

14.50 times 3 is 43.50

The answer is $14.50

6 0

3 years ago

Identify the triangle PQR as isosceles (two sides of equal length), equilateral (three sides of equal length), or a scalene

Ipatiy [6.2K]

Answer:

Isosceles

Step-by-step explanation:

In order to figure what type of triangle this is out, we need to start by plotting the given points. That will help us visualize the triangle better and see if our conclusions make sense. (See attached picture).

Once we got the triangle, the strategy to follow is to use the distance between two points formula to see what the measurement of each side of the triangle is. This will help us determine if 2, 3 or none of the sides of the tirangle are the same.

The distance formula is the following:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

so now we can find the desired distances, let's start with the distance between P and Q:

$|PQ|=\sqrt{(-4-0)^{2}+(9-8)^{2}}$

which yields:

$|PQ|=\sqrt{17}$

next, let's find the distance between P and R:

$|PR|=\sqrt{(-4-(-3))^{2}+(9-5)^{2}}$

which yields:

$|PR|=\sqrt{17}$

and finally the distance between Q and R:

$|QR|=\sqrt{(0-(-3))^{2}+(8-5)^{2}}$

which yields:

$|QR|=3\sqrt{2}$

As you may see from the result, only two of the three sides are the same, |PQ| and |PR|, so this will be an Isosceles triangle.

6 0

2 years ago

A lighthouse beacon can be seen 17mi in all directions. To the nearest square mile, what is the area over which the beacon can b

Alchen [17]

Imagine this as a circle. The circle will have a radius of 17mi and the lighthouse will be in the middle. The area of the circle will be the area over which the beacon can be seen.

$A=\pi r^{2}$ is the equation for the area of the circle where A is the area.

Now we simply plug in our information

A= $\pi (17)^{2}$
A=907.9 $mi^{2}$