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algol13
4 years ago
12

It costs $3.45 to buy 3/ 4 lb of chopped walnuts. How much would it cost to purchase 7.5 lbs of walnuts?

Mathematics
2 answers:
Softa [21]4 years ago
8 0

Answer:

It would cost $ 34.5

Step-by-step explanation:

Given,

The cost of \frac{3}{4} lb of chopped walnut = $ 3.45,

So, the cost of 1 lb of chopped walnut = \frac{4}{3}\times 3.45

=4\times 1.15

= $ 4.6,

Thus, the cost of 7.5 lbs of walnuts = 7.5 × cost of 1 b of walnut

= 7.5 × 4.6

= $ 34.5

Dmitry_Shevchenko [17]4 years ago
7 0

Answer:

The cost of the 7.5 lbs of walnuts be $2.16 .

Step-by-step explanation:

As given

It costs $3.45 to buy \frac{3}{4} lb of chopped walnuts.

i.e

\$ 3.45 = \frac{3}{4}\ lb

Now calculate the cost of one pound .

Cost\ of\ one\ pound = \frac{3.45}{\frac{3}{4}}

Cost\ of\ one\ pound = \$ 0.2875

Now calculated the cost of the 7.5 lbs of walnuts .

Cost of 7.5 lbs of walnuts = 7.5 × 0.2875

                                           = $2.16 (Approx)

Therefore the cost of the 7.5 lbs of walnuts be $2.16 .

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Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m
Harlamova29_29 [7]

Answer:

47.4167

D. The computed mean is close to the actual mean because the difference between the means is less than 5%

Step-by-step explanation:

Given the distribution :

Speed(m/hr) ___ midpoint(x) ___ F ___fx

42 - 45 _______ 43.5 ________21 __ 913.5

46 - 49 _______47.5 _________15 __712.5

50 - 53 _______ 51.5 _________6 __ 309

54 - 57 _______ 55.5 ________ 4 ___ 222

58 - 61 ________59.5 ________ 2 ___ 119

The midpoint, x= sum of lower and upper boundary divided by 2

For instance, (42 + 45) / 2 = 43.5

The computed mean, Σfx / Σf = 2276 / 48 = 47.4167

Actual mean = 47.3 miles

(47.4167 - 47.3) / 47.3 * 100% = 0.24%

6 0
3 years ago
Jackson is two times older than Shelly. If the sum of their ages is 18, how old is Jackson?
salantis [7]
Answer: jackson is 12

explanation:
let the age be represented by x
jackson is 2 times older than shelly so
2x is jackson’s age and x is shelly’s age

since the sum of their ages is 18 then:
2x + x = 18

solve:
3x = 18 ➔ divide by 3 on both sides
x = 6

so now we know shelly is 6

jackson is 2 times older than her so:
2(6) = 12

6 0
3 years ago
Read 2 more answers
The equation (x-3)^2+(y+7)^2=64 models the position and range of the source of a radio signal. Describe the position of the sour
12345 [234]
\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2}
\\\\\\
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so, the broadcast location and range is more or less like the picture below.

7 0
3 years ago
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How does the 2 in the hundredths place compare to the 2 in the thousandths place?
dybincka [34]

Answer:

2 in the hundredths place is greater

Step-by-step explanation:

2 in the hundredths place is 10 times the thousands place

7 0
4 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
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