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gregori [183]
3 years ago
13

5a + 3b + c= 40 a-3b+2c= -10 14a-2b+3c= 50

Mathematics
1 answer:
aalyn [17]3 years ago
8 0

Answer:

a= 40-3b-c/5

a=-10+3b-2c

a=50+2b-3c/14

Step-by-step explanation:

5a+3b+c-(3b+c)=40-(3b+c)

5a=40-3b-c

5a/5=40/5-3b/5-c/5

a= 40-3b-c/5

a-3b+2c-(3b+2c)=-10-(-3b+2c)

a=-10+3b-2c

14a-2b+3c-(-2b+3c)=50-(-2b+3c)

14a=50+2b-3c

14a/14=50/14+2b/14-3c/14  

a=50+2b-3c/14

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Step-by-step explanation:

<em>Step 1: Define general form of equation of line</em>

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That equation passes 2 points, which are represented in form of (x, y), (3, 7) and (6, 8).

Substitute these values of x and y into the original equation in step 1:

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<em>Step 3: Solve the system of equations in step 2 for M</em>

Subtract 1st equation from 2nd equation:

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Hope this helps!

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