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3 years ago

Sucesión II: 3, 7, 11, 15, 19, 23 ... ¿Cual es la expresión algebraica que la genera? * x=4n-2 x= 4n-1 x=3n-2

Mathematics

1 answer:

LenaWriter [7]3 years ago

8 0

Responder:

4n-1

Explicación paso a paso:

Dada la secuencia

3, 7, 11, 15, 19, 23 ..

El enésimo término si la secuencia se expresa como;

Tn = una + (n-1) d

a es el primer término = 3

n es el número de términos

d es la diferencia común = 7-3 = 11-7

d = 4

Sustituir

Tn = 3+ (n-1) (4)

Tn = 3 + 4n-4

Tn = 4n-1

Por lo tanto, el enésimo término de la secuencia es 4n-1

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Step(ii):-

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