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2 years ago

Sucesión II: 3, 7, 11, 15, 19, 23 ... ¿Cual es la expresión algebraica que la genera? * x=4n-2 x= 4n-1 x=3n-2

Mathematics

1 answer:

LenaWriter [7]2 years ago

8 0

Responder:

4n-1

Explicación paso a paso:

Dada la secuencia

3, 7, 11, 15, 19, 23 ..

El enésimo término si la secuencia se expresa como;

Tn = una + (n-1) d

a es el primer término = 3

n es el número de términos

d es la diferencia común = 7-3 = 11-7

d = 4

Sustituir

Tn = 3+ (n-1) (4)

Tn = 3 + 4n-4

Tn = 4n-1

Por lo tanto, el enésimo término de la secuencia es 4n-1

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$\text { Simple interest }=\frac{\text {Principal} \times r a t e \times T i m e}{100}$

In the question it is given that Simple interest earned from both the investments at the end of the year is $3980.

Using the given below equation, we will try to find out the investments at each rate.

$\begin{array}{l}{\frac{x \times 5 \times 1}{100}+\frac{(66000-x) \times 7 \times 1}{100}=3980} \\\\ {\frac{5 x}{100}+\frac{462000-7 x}{100}=3980} \\\\ {\frac{5 x+462000-7 x}{100}=3980} \\\\ {-2 \mathrm{x}+462000=3980 \times 100} \\\\ {-2 \mathrm{x}=398000-462000} \\\\ {-2 \mathrm{x}=-64000} \\\\ {\mathrm{x}=\frac{-64000}{-2}}\end{array}$

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