Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
Answer:
Remove all perfect squares from inside the square root. ... I think it's about eighth or ninth grade. ... so if you have the cube root of the square root of (x-5) =2, you get ((x-5)^(1/2))^1/3 = 2, power to power requires multiplication, so (x-5)^1/6 = 2, ...
Missing: 176 xy
Given data
1. The mean
2. The median
3. The sample standard deviation
![\begin{gathered} SD\text{ =}\sqrt[]{\frac{\sum f|x-\bar{x}|}{\sum f}} \\ \bar{x}=7.6515 \\ SD=\sqrt[]{4.8028} \\ SD=2.1915 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20SD%5Ctext%7B%20%3D%7D%5Csqrt%5B%5D%7B%5Cfrac%7B%5Csum%20f%7Cx-%5Cbar%7Bx%7D%7C%7D%7B%5Csum%20f%7D%7D%20%5C%5C%20%5Cbar%7Bx%7D%3D7.6515%20%5C%5C%20SD%3D%5Csqrt%5B%5D%7B4.8028%7D%20%5C%5C%20SD%3D2.1915%20%5Cend%7Bgathered%7D)
Answer:
y= -10x+200, x is equal to a week
Step-by-step explanation:
formula y=mx+b
we lose 10$ a week so the slope is -10 and we start with a base amount of 200
so plug those numbers in and you have y= -10x+200
