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Vesnalui [34]
3 years ago
12

Sonya has 48 dolls. She wants to store them in boxes each box holds 7 dolls what is the least amount of boxes that Sonya will ne

ed to store all her dolls
Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0
She will need 6 boxes so she will have 6 more boxes left over
DENIUS [597]3 years ago
5 0
She will need to use 6 of the boxes
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He would need to play 12 average scoring games.
900 (goal) - 300 (has) = 600
and 600/50 is 12 
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3 years ago
Write a common denominator for 1/4 and 5/6
maxonik [38]
A common denominator is 12
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Solve for x.<br> (x - 12)<br> 2x<br> 51
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114

Step-by-step explanation:

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The engineers designing the All Aboard Railroad between Boca Raton and Jupiter decide to create parallel tracks through this por
olga2289 [7]

Answer:

there are no signs between the x and y and constant

it could be

2x+5y=15

2x+5y=-15

-2x+5y=15

2x-5y=15

for ax+by=c, the equation of a line paralell to that is

ax+by=d where a=a, b=b, and c and d are constants

(for this answer, I'm going to use 2x+5y=15)

given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d

to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant

2x+5y=d

2(4)+5(-2)=d

8-10=d

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the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15

pls mark me brainlest

5 0
3 years ago
a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di
Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}

Thus, the total prototypes will cost around $60.75

7 0
1 year ago
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