All categories

3 years ago

What is the answer to 3+(1+p)=12

Mathematics

1 answer:

nydimaria [60]3 years ago

3 0

3+(1+p)=12
3+1(1+p)=12
3+1+p=12
4+p=12
p=8

You might be interested in

How can i add the fractions using a giant one to create a conmon 1 denominator /4+5/8

Mice21 [21]

Stack them on top of each other and find the common denominator then multiply to total the denominator. Ex. 1/4 denominator is 8. 4x2 is 8. So 1 times what equals 8. 1! Then you should a new fraction 8/8 which is equivalent to 1.

8 0

3 years ago

PLEASE i need help

____ [38]

1. 8^3 * 8^2, 8^5, and (2^3)^5
2. 6^9, and 6^5 x 6^4

6 0

3 years ago

A ------------ is one of one hundred equal parts of a whole. ( decimal , decimal point, hundred , hundredth)

oee [108]

Decimal point is the right answer

5 0

3 years ago

Read 2 more answers

The sum of three integers is 12

Liula [17]

The three integers are 5,17 and -10

Step-by-step explanation:

Let x, y and z be three integers then

$x+y+z=12 \ \ \Eqn\ 1$

'The sum of the first and second integers exceeds the third by 32'

$x+y=z+32\ \ \ \ Eqn\ 2$

The third integer is 15 less than the first.

$z=x-15\ \ \ \ Eqn\ 3$

From Eqn 2:

$x+y=z + 32\\x+y-z=32$

Subtracting Eqn 1 from eqn 2

$x+y-z-(x+y+z)=32-12\\x+y-z-x-y-z=20\\-2z=20$

Dividing both sides by -2

$\frac{-2z}{-2}=\frac{20}{-2}\\z=-10$

Putting z=-10 in Eqn 3

$z=x-15\\-10=x-15\\x=15-10\\x=5$

Putting x=5 and z=-10 in Eqn 1

$x+y+z=12\\5+y-10=12\\y-5=12\\y=12+5\\y=17\\$

Hence,

The three integers are 5,17 and -10

Keywords: Linear Equations, Variables

Learn more about linear equations at:

#LearnwithBrainly

3 0

2 years ago

Read 2 more answers

ANSWER QUICKLY PLEASE Solve for x 1 < x + 3 <4

Degger [83]

Answer:SCAMBODALEETDODODO

Step-by-step explanation:

TOM HOLLAND IS MY HUSBAND DID U KNOW THAT?!

8 0

2 years ago

Read 2 more answers