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avanturin [10]
3 years ago
10

A student has taken three math tests so far this semester. His scores for the first three tests were 71, 75, and 79. Part A: Sup

pose his test scores continue to improve at the same rate. What will be the grade on the sixth and (final) test?
Mathematics
1 answer:
valina [46]3 years ago
5 0

Answer:

The grade of this sixth and (final) test <u>would be 91</u>.

Step-by-step explanation:

This is an arithmetic series since each time the data is increasing by the common difference of 4, and we already know a₁ which is the first term in the sequence is 71, therefore we can say:

a₁ = 71

r = 4

a₆ = the sixth term that needs to be found out

n = 6

Formula of an arithemetic series:

aₙ = a₁ + r(n - 1)

a₆ = 71 + 4(6 - 1)

a₆ = 71 + 4(5)

a₆ = 71 + 20

a₆ = 91

Hence, the grade of this sixth and (final) test would be 91.

Hope this helps!

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<h3><u>Answer :- </u></h3>

  • The total surfAce area of cone is <u>1244.57m².</u>

<h3><u>Step-by-step</u><u> </u><u>explanation</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>To </u><u>find </u><u>:</u><u>-</u><u> </u>

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<h3><u>Solution :- </u></h3>

Given that ,

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<h3><u>♦</u><u> </u><u>Radius is </u></h3>

<u>=</u>> Diameter / 2

=> 24 / 2

=> 12m

<h3>As we know that , </h3>

<u>Total surface area of cone = πr ( r + L ) .</u>

<h3><u>Where</u><u> </u><u>we </u><u>know</u><u>,</u></h3>

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<h3>According to the question :- </h3>

The total surface of cone is,

<u>=> Total surface area = πr { r + L } ..</u>

=  \frac{22}{7}  \times 12 \times (12 + 21)

=  \frac{22}{7}  \times 12 \times 33

= (22 \times 12 \times 33) \div 7

= (726 \times 12) \div 7

= 8712 \div 7

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• Therefore , The total surface area of cone is <u>1244.57m².</u>

Hope this helps you :)

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