I’m afraid you can’t delete , unless if we report it or else there’s no other way
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
Answer: to
this answer is attached to the picture
Note: Let us consider, we need to find the
and
.
Given:
In the given figure, BD is the angle bisector of ABC.
To find:
The
and
.
Solution:
BD is the angle bisector of ABC. So,




Divide both sides by 2.


Now,



And,





Therefore,
and
.
Answer:
x > - 3/7
Step-by-step explanation:
6x - 2x - 4 > 2 - 3 (x + 3)
6x - 2x - 4 > 2 - 3x - 9
4x - 4 > 2 - 3x - 9
4x - 4 > - 7 - 3x
4x - 4 + 3x > - 7
7x > - 7 + 4
7x > - 3