Linear functions have to have the same slope between any 2 points
find the slope betwen them
slope betwen 2 points (x1,y1) and (x2,y2) is
(y1-y1)/(x2-x1)
given
(1,12) and (3,9)
slope=(9-12)/(3-1)=-3/2
if we wanted to chek furthere, we check (3,9) and (5,6) and fnd that the slope is also -3/2
so
y=mx+b
m=slope
b=yint
y=-3/2x+b
find b
if x=1 then y=12
12=-3/2+b
add 3/2 both sides
12+3/2=b
13+1/2=b
26/2+1/2=b
27/2=b
y=-3/2x+27/2
try them
we have 2 x values
7 and 3
input them and see their outputs
for x=7
y=-3/2(7)+27/2
y=-21/2+27/2
y=6/2
y=3
(7,3) is a valid point
for x=3
hold a second, we already have a x=3
it is (3,9)
none of them
answer is (7,3)
The correct answer for the question that is being presented above is this one: "(4,1)."
The distance from (0,1) to (0,6) is 5 units.
The area of a triangle is
Area = bh/2
10 = 5b/2
20 = 5b
b = 4
The distance of the base is 4 units. So, from (0,1) count 4 units to the right but on the same y coordinate.
So the point is in (4, 1).
The answer is B and put the question next time