Given f(x) = x2 + 5 and g(x) = x^2 , and h(x) = -2x what is h(g(f(x)))=

Mathematics

1 answer:

jeyben [28]3 years ago

5 0

Answer:

Step-by-step explanation:

f(x) = x^2 + 5

g(x^2 + 5) = (x^2 + 5)^2= x^4 + 5x^2 + 5x^2 + 25 = x^4 + 10x^2 + 25

h(x^4 + 10x^2 + 25)= -2(x^4 + 10x^2 + 25)

-2x^4 - 20x^2 - 50

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joja [24]

Answer:

3 inches

Step-by-step explanation:

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3 years ago

Read 2 more answers

The question is in the picture

otez555 [7]

Answer:

x=27.8

Step-by-step explanation:

first, you need to find y. 2y-5=65. 65+5 is 60 and you are left with 2y=70. to get the 2 off of the y you divide everything by 2. 70/2 is 35 therefor y=35. Now you plug that into the other equation (2x+y) and get 2x+35 which is equal to segment 90.6 so 2x+35=90.6. subtract 35 on both sides and you have 2x=55.6. To get the 2 off the x, we divide everything by 2. all of that divided by 2 is x=27.8

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2 years ago

I need answers 1-4 please!

madreJ [45]

1. Horizontal asymptotes: None
Vertical asymptote: x=-2
RD: 2
Domain: First picture
Range: first pic

2.HA: y=1
VA: x= -5 negative
RD: x= 5 no negative
Domain: second pic
Range second pic

3.HA: y=0
VA: x=-4,4
RD: none
D: 3rd pic
R: 3rd pic

4.HA: none
VA: x=3
RD: x=-2
D: 4th
R: 4th

I hope this helps!!!!!!!