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olya-2409 [2.1K]
4 years ago
10

The normal boiling point of water is 100.0 °c and its molar enthalpy of vaporization is 40.67 kj/mol. what is the change in entr

opy in the system in j/k when 51.1 grams of steam at 1 atm condenses to a liquid at the normal boiling point?
Chemistry
1 answer:
Gnesinka [82]4 years ago
6 0
We are going to use this formula:

Δ H = T * ΔS

when Δ H is the change in enthalpy 

and T is the temperature in Kelvin = 100+273= 373 K

and ΔS is the change in entropy

but first, we need to get the value of ΔH:

ΔH = mass * molar mass per mole * enthalpy of vaporization

by substitution:

ΔH = 51.1 g * (1 mole/18g) * 40.67KJ/mole

      = -115.5 KJ

we use negative sign because this is an exothermic reaction.

by substitution on the first formula, we will get the change of entropyΔS:

ΔS = ΔH / T

     = -115.5 KJ / 373K

     = 310 J/K
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A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.
Alenkinab [10]

Answer:

\Delta V = 234.736\,mL

Explanation:

The quantity of moles of ethanol in the solution is:

n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)

n_{C_{2}H_{5}OH} = 4.985\,mol

The mass and volume of ethanol in the solution are, respectively:

m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)

m_{C_{2}H_{5}OH} = 229.658\,g

V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }

V_{C_{2}H_{5}OH} = 290.964\,mL

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)

\Delta V = 234.736\,mL

8 0
3 years ago
What is the independent variable when testing to see how the viscosity of a liquid affects its flow rate
DedPeter [7]

Answer:

Viscosity

Explanation:

The viscosity of the liquid is the independent variable. The flow rate is the dependent variable in this hypothesis.

The statement given is called the hypothesis. It is a form of scientific guess into a phenomenon.

  • An independent variable is the cause.
  • A dependent variable is the effect produced.
  • In this hypothesis, the cause of the various flow rate of the liquid is the viscosity.
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  • The flow rate is the dependent variable.
3 0
3 years ago
Acenaphthylene, a hydrocarbon that is a constituent of a coal tar, is 94.71% and has a molar mass of 152.19 g/mol. What are the
dolphi86 [110]

Answer:

From what I personally know, Acenaphthylene 75%. Empirical Formula (Hill Notation): C12H8. CAS Number: 208-96-8. Molecular Weight: 152.19. Beilstein: 774092. EC Number:

Explanation:

Acenaphthylene, a polycyclic aromatic hydrocarbon is an ortho- and peri-fused tricyclic hydrocarbon. The molecule resembles naphthalene with positions 1 and 8 connected by a -CH=CH- unit. It is a yellow solid. Unlike many polycyclic aromatic hydrocarbons, it has no fluorescence. Acenaphthylene/Formula is C12H8.

I'm not sure if this will help you but this is what I know so I hope it does :)

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Oxidation states of N2 + 3H2 --> 2NH3
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True because n on both sides are 2 and the hydrogen on both sides are 6
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If ammonia is manufactured at 356 k, is the reaction spontaneous, given that the enthalpy and entropy change for the reaction ar
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The reaction will be spontaneous if Gibb free energy is negative, according the following relation:  
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In the case of ammonia:  
G = -93000 - 356*(-198) = -93000 + 70488 = -22512 j/mol  
As G < 0 then the reaction is spontaneous.
5 0
4 years ago
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