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kogti [31]
3 years ago
15

Which statements about β turns are correct? Their purpose is to reverse the direction of the polypeptide chain. There are two ty

pes, I and II, which differ mainly in the conformation about the i+1 and i+2 residue amide bond. They typically contain large, hydrophobic residues. Their conformation is held in place through H bonds.
Chemistry
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

The correct answer is - 1, 2, and 4 statements.

Explanation:

Beta and gamma turns are common plots or turns in proteins and contain intra-turn hydrogen bonds. This hydrogen bond is present between CO of residue i and NH of residue i+3 that holds the confirmation in beta turns.

Beta turns, assist the protein to get their globularity, as the aim of beta turns is to reverse the direction of the polypeptide. The two main of beta turns are type-I and type-Il. and their minor images are type-I and type-Il.

Thus, the correct answer is - 1, 2, and 4 statements.

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Find the cell potential for a system whose ∆G = +55 kJ and 3 moles of electrons are exchanged.
rosijanka [135]

Answer:- cell potential = -0.19 volts

Solution:- The equation that shows the connection between \Delta G and cell potential, E is written  as:

\Delta G=-nFE

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is \frac{96485C}{mol} .

It asks to calculate the value of E, so let's rearrange the equation:

E=-\frac{\Delta G}{nF}

Let's plug in the values in it:

E=-\frac{55kJ}{3mol*96485C.mol^-}

E=-\frac{0.00019kJ}{C}

since, \frac{1kJ}{C}=1000V

Where C stands for coulombs and V stands for volts.

So, E=-\frac{0.00019kJ}{C}(\frac{1000V}{\frac{1kJ}{C}})

E = -0.19 V

So, the cell potential is -0.19 volts.


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