Answer: HCI + KOH → KCI + H20
Explanation:
HCI(aq) + KOH(aq) → KCI(aq) + H20(l)
Acid + base → Salt + Water.
The above is a neutralization reaction in which an acid, aqeous HCl reacts completely with an appropriate amount of a base, aqueous KOH to produce salt, aqueous KCl and water, liquid H2O only.
This is a neutralization reaction since, the hydrogen ion, H+, from the HCl is neutralized by the hydroxide ion, OH-, from the KOH to form the water molecule, H2O and salt, KCl only.
Answer:
6⅔ shifts
Explanation:
From the question given:
A shift = 4 hours
Pay = $8.25 per hour
Next, we shall determine the number of hours that will result in a pay of $220. This can be obtained as follow:
$8.25 = 1 hour
Therefore,
$220 = $220 × 1 hour / $8.25
$220 = 220/8.25 hours.
$220 = 80/3 hours
$220 = 26⅔ hours
Therefore, it will take 26⅔ hours to receive a pay of $220.
Finally, we shall determine the number of shifts in 26⅔ hours. This can be obtained as follow:
4 hours = 1 shift
Therefore,
26⅔ hours = 26⅔ ÷ 4
26⅔ hours = 80/3 × 1/4
26⅔ hours = 80/12
26⅔ hours = 20/3
26⅔ hours = 6⅔ shifts
Therefore, she will work 6⅔ shifts in order to receive a pay of $220
to be as exact as i can it is all of them they all work together to make water good.
Answer:
The 
for the reaction 
will be 4.69.
Explanation:
The given equation is A(B) = 2B(g)
to evaluate equilibrium constant for
![K_c=[B]^2[A]](https://tex.z-dn.net/?f=K_c%3D%5BB%5D%5E2%5BA%5D)
= 0.045
The reverse will be 
Then, ![K_c = \frac{[A]}{[B]^2}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5BA%5D%7D%7B%5BB%5D%5E2%7D)
= 
= 
The equilibrium constant for will be
= 4.69
Therefore, for the reaction will be 4.69.
