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Gelneren [198K]
3 years ago
15

76.

Biology
1 answer:
yarga [219]3 years ago
6 0

Answer:

Happy cats blink eyes, keep whiskers forward and tail relaxed; Aggressive Cat lowers tail and make it stiff, crouches etc; an Angry cat is rigid and curls itself around its body and a Depressed cat sleeps more than usual.

Explanation:

A Veterinary  assistant must be well aware about different body languages of cat. Cats show different body postures in different moods.  

i) HAPPY CAT- A happy cat returns our gaze with a blink an eye and there will be a dilation in the eye that indicates happiness and tail will be relaxed.

ii) AGGRESSIVE CAT- An aggressive cat can both be defensive and offensive. Offensive body language includes- stiff and straight leg, lowered stiff tail and a defensive language includes- Crouching of body and eyes completely dilated.

iii) ANGRY CAT- Angry cat has a rigid posture, growls and make its body curled up and make itself look large.

iv) DEPRESSED CAT- Depressed cats hold its ear back and make their fur stand at the end, they tuck their tail and sleeps more than usual.

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3 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

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Answer:

The suns average density is greater than water's.

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