Probability that the child would be homozygous for the g542x allele 0.00
<h3>why the probability is nil?
</h3>
- The kid cannot be homozygous for the G542X gene since only the mother has it; the father, on the other hand, has a mutant dF508 allele and so cannot pass on a copy of mutant G542X = never homozygous recessive child.
- A kid must have the G542X allele from both parents in order to be homozygous for the G542X allele. Because only the mother possesses the G542X gene, the child's chances of being homozygous for the G542X allele are 0.00
<h3>
When offspring show a blend of the parents traits one allele is dominant over the other?</h3>
- At the point when one allele is predominant over another, posterity show a mix of guardians' qualities.
- The heterozygous aggregate in complete predominance is tracked in the middle of between two homozygous aggregates. A heterozygous individual showcases qualities of the two guardians in the event of codominance.
To learn more about hetrozygous from the given link
brainly.com/question/1626661
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Chlorophyll molecules allow the plant to absorb sunlight which is vital for photosynthesis
To see the difference between <span>biped and a quadruped,</span> let's compare the skeletons of the man (biped) and the horse (quadruped):
*The man has the bigger pelvis: he has to bear the weight of the body.*The scapula is smaller.*The bones of the hind leg bigger.*The forearms more mobile.*The man has the spine that attaches under the skull.*And the tail that has completely regressed.
the man has adapted to standing and biped (he walks on 2 feet): his hind legs are reinforced.
Answer:
Okay what is the assignment?
