Question

URGENT! Please and Thanks :)

Answer 1

For this case we will define the following:
 A, B: are the values of the triangle angles
 a, b: are the values of the lengths of the sides opposite the angles A, B.
 We then have to use the law of the sine:
 $\frac{sinB}{b} = \frac{sinA}{a}$
 Clearing the angle B we have:
 $sinB = \frac{sinA}{a}*b$
 $B = arcsin(\frac{sinA}{a}*b)$
 Substituting values we have:
 $B = arcsin(\frac{sin113}{200}*134)$
 $B = 38.08$
 Answer:
 the following is true:
 A. angle B=38.08 degrees