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2 years ago

The lateral surface area of a right square pyramid is given by s - 82.492. If the pyramid has height 10 feet and lateral surface

Mathematics

1 answer:

anyanavicka [17]2 years ago

4 0

Answer:

a is the answer.

Step-by-step explanation:

S- 82.492 = Perimeter base x height /2 + base

Pyramid base

b x 10h = hb /2 + b = 100

6.92586 x 6.92586 x 10 = 479.675367396/2 =239.837683698+ base 47.9675367396 =287.805220438

479.675367396- 287.805220438 = 191.870146958

Proving each rectangle pyramid side is 1/4 of 287.805220438/4 = 72 +10 height =S- 82 (S = 82.492)

then 192/2 = 96 = 100 square feet

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