The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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Answer:
The range is f(x) ≥ 0
Step-by-step explanation:
The range of the function is defined as the set of values of the dependent variable for which the function is defined.
Here the function f(x) = 1/2 √x is defined for all values of x which are greater than or equal to zero or we can say all non-negative real numbers.
So, the range is f(x) ≥ 0
8 × 46 = 8 × (40 + 6) = (8 × 40) + (8 × 6) = 320 + 48 = 368
Hope this explains it.
Answer:
No it is not a relation function if im correct there are two 5 x values so
Step-by-step explanation:
Answer:
b=d
x=
bStep-by-step explanation:
