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3 years ago

Maynor rode his bike 2 miles in 8 minutes. Paul rode his bike

Mathematics

1 answer:

madam [21]3 years ago

7 0

no because maynor rode 2 miles every 4 minutes and paul rode 3 miles every 4 minutes. not the same

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30000 at 8% per year for 10 months equals to

motikmotik

Answer:

2000

Step-by-step explanation:

S.I=P×rate / 100×time

30000×8 / 100×5/6

=2000

3 0

3 years ago

The figure below shows the design of a truss to support the weight of a roof. In this truss design, ∠A⩭∠D and ĀF⩭DF.

bearhunter [10]

Answer:

$m\angle A= 30^{\circ}$

Step-by-step explanation:

In the question, we're given $\angle A\cong \angle D$ . Therefore, the measure of these two angles must be equal.

To find the value of $x$ , set these two angles equal to each other:

$4x-26=x+16$

Add 26 and subtract $x$ from both sides:

$3x=42$

Divide both sides by 3:

$x=\frac{42}{3}=14$

Since $\angle A$ was labelled as $4x-26$ , substitute $x=14$ to find its measure:

$\angle A=4(14)-26,\\\angle A=56-26,\\\angle A=\boxed{30^{\circ}}$

You can also substitute $x=14$ into the label of angle D as angle A is congruent to angle D for easier calculations ( $14+16=\boxed{30^{\circ}}$ ).

5 0

3 years ago

Math question down below

mezya [45]

y=1 is the answer, there is no slope, so the formula y=mx+b turns into y=b, since 1 is the intercept 1 is b.

6 0

3 years ago

Read 2 more answers

What does 6.08×3.15 equal

faltersainse [42]

6.08 times 3.15 is 19.152.

3 0

3 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

3 years ago