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andrew-mc [135]
3 years ago
8

Suppose that the weight (in pounds) of an airplane is a linear function of the amount of fuel (in gallons) in its tank. When car

rying 10 gallons of fuel, the airplane weighs 2064 pounds. When carrying 45 gallons of fuel, it weighs 2288 pounds. How much does the airplane weigh if it is carrying 60 gallons of fuel?
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

Now, to answer the question, we need to add the weight of (58-42) = 16 gallons of fuel to the weight of the plane

carrying 42 gallons of fuel, 2331 pounds.

So, the answer is 2331 + 16*5.5 = 2419 pounds.

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Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

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