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Aleks [24]
3 years ago
10

$8.49×6=□ $509.40 $50.94 $50.93 $5.09

Mathematics
2 answers:
Alex787 [66]3 years ago
7 0
Answer is 50.94 dollars
tangare [24]3 years ago
5 0

Answer:

hahahaha sorry its 50.94

Step-by-step explanation:

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14. 3/64 + 2/32 + 5/16 = <br>what is the answer ​
Anit [1.1K]

Answer:

27/64

Step-by-step explanation:

(7×16)+(5×64)64×16

=112+3201/024

=432/1024

Simplifying 432/1024, the answer is

=27/64

3 0
2 years ago
Read 2 more answers
Find the distance between the two points.
Ksenya-84 [330]

Hey there!

Distance formula:

d = \sqrt{(x_{2}-x_{1})+(y_{2}-y_{1}) }

Plug in variables:

d = \sqrt{(0-(-6))+(0-(-7))}

Simplify.

d = \sqrt{6+7}

d = \sqrt{13}

The distance between the two points is \sqrt{13}  units.

Hope this helps!

4 0
3 years ago
 For the equation 2n - 3 = 7
Stells [14]

Answer:

The variable is n

The coefficient is 2

And the solution to n is 10.

Step-by-step explanation:

The number in the equation is the variable. The coefficient is the number before the variable. And a number next to a letter means you multiply. So 2*5=10 10-3=7

5 0
2 years ago
Read 2 more answers
The expression 9x2 - 5x - 7 has ___ terms and a constant of ___.
elena55 [62]
Answer: first option 3, - 7

Justification:

1) Given expression:9x² - 5x - 7

2) Each monomial is a term.

The monomials are each  combination of numbers and letters (coefficient, letters and exponents) separated of other monomials (terms) with a + or - operator.

3) Therefore, there are 3 terms which are:

9x²,
-5x, and
-7.

The polynomials with 3 terms are called monomials.

4) The monomial (term) withoud letter is the constant. In this case that is  -7.
4 0
3 years ago
Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = −sin x, [0,
deff fn [24]

Answer with Step-by-step explanation:

We are given that

f(x)=-sin x

[0,\infty]]

Average value of the function is given gy

f_{avg}=\frac{1}{b-a}\int_{a}^{b}f(x)dx=\frac{1}{\pi-0}\int_{0}^{\pi}-sinx dx

f_{avg}=\frac{1}{\pi}[cosx]^{\pi}_{0}

Using the formula

\int sin xdx=-cos x

f_{avg}=\frac{1}{\pi}(cos\pi-cos0)

f_{avg}=\frac{1}{\pi}(-1-1)=-\frac{2}{\pi}

f(x)=f_{avg}

-sinx=-\frac{2}{\pi}

sinx=\frac{2}{\pi}

x=sin^{-1}(\frac{2}{\pi})=0.69radian

7 0
2 years ago
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