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3 years ago

What number is halfway between 13 and 31

2 answers:

8 0

The distance between the numbers A and B is equal |B-A|

$Simplify:\\\\\frac{|31-13|}{2}=\frac{|18|}{2}=\frac{18}{2}=\boxed{9}$

ankoles [38]3 years ago

4 0

To find the answer to that, you have to see how many numbers are between 13 and 31. There are 18 numbers between 13 and 31. Divide 18 by 2 and you will get the number halfway. 9 is halfway between 13 and 31. So, add 9 to 13 and you get 22.

The answer is 22.

Hope I helped

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Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1

Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in $\frac{1}{1.5}$ minutes

Hence

10.50 mph will be increased in $\frac{1}{1.5} \times 10.50$ minutes

$= \frac{10.5}{1.5}$

$=7$

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0

2 years ago

5x-6y=3 <br> 7y=2x+8 <br> Help me out please

zaharov [31]

Answer:

A) 5x-6y=3

B) 7y=2x+8

B) -2x + 7y = 8 then multiplying "B" by 2.5

B) -5x +17.5y = 20 then adding this to A

A) 5x -6y = 3

11.5y = 23

y = 2

x = 3

Step-by-step explanation:

3 0

3 years ago

Write an expression to represent the circumference of the following circle.

Stells [14]

Answer:

Step-by-step explanation:

it's option d bro...becoz

x + 10 is the diameter

3 0

3 years ago

By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i < ji

Dafna11 [192]

Answer:

There are a total of ${ 6 \choose 3} = 20$ functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

${6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20$