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vladimir2022 [97]
3 years ago
12

Whats 85 divided by 3

Mathematics
2 answers:
lara [203]3 years ago
6 0
28.3 is the answer in 1 decimal place!
Fynjy0 [20]3 years ago
4 0
The answer is 28.33
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At sea level, earths atmosphere exerts a pressure of 1 atmosphere. Atmospheric pressure P (in atmospheres) decreases with altitu
PtichkaEL [24]

Answer:

Initial Amount=1

Decay Factor=0.99987

Decay Rate=0.013%

Step-by-step explanation:

If P = 0.99987ᵃ

I. Initial amount

The initial amount is when a=0

P = 0.99987⁰ = 1

The Pressure at Sea Level=1

II. Decay factor

This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.

III. Decay Rate = 1-0.99987 = 0.00013

Expressed in Percentage = 0.013%

5 0
3 years ago
Read 2 more answers
what number must be added to 3 and 8 so that the ratio of the first number to the second number is equal to 3 :4​
Grace [21]
The answer is 12.
Steps
If that number is x
(3+x)/(8+x)=3/4
"Cross multply"
4(3+x)=3(8+x)
12+4x=24+3x
x=12
To check: add 12 to 3 and 8. 3+12=15 and 8+12=20. 15/20=3/4
3 0
3 years ago
Help!! use division to change each fraction to a decimal
lakkis [162]
4/5=0.8
1/50=0.02
 Hope that helps

5 0
3 years ago
Read 2 more answers
Yo what's 0.994 rounded to the nearest tenth
krek1111 [17]

Answer:To round 0.994 to the nearest tenth consider the hundredths’ value of 0.994, which is 9 and equal or more than 5. Therefore, the tenths value of 0.994 increases by 1 to 0.

0.994 rounded to the nearest tenth = 1.0

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} }

but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0
3 years ago
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