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lubasha [3.4K]
3 years ago
5

Which number can each term of the equation be multiplied by to eliminate the fractions before solving ? -3/4 m-1/2=2+1/4mA 2B 3C

4 D 5
Mathematics
2 answers:
bixtya [17]3 years ago
7 0

The correct answer is C. 4.

Typically, we look to multiply by the bottom number (the denominator) in order to get fractions to cancel out. If we multiply 1/6 by 6, we get just 1, which is why we do it.

In this problem, you have two different denominators, 2 and 4. If you multiply them all by 2, the term -3/4m will still be a fraction.

-3/4m * 2 = -3/2m

As a result, we must try 4 instead. This causes all of them to cease being a fraction. Even the one with 2 as a denominator.

-1/2 * 4 = -2

qaws [65]3 years ago
4 0

the correct answer is option;

c

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Let X denote the number of flaws along a 100-m reel of magnetic tape (an integer-valued variable). Suppose Zdenote the number of
Lemur [1.5K]

Answer:

a) P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)

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And we can find this probability like this:

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b) P(X \leq 30)= P(X

And using the z score we got:

P(X

c) P(X

And if we use the continuity correction we got:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Continuity correction means that we need to add and subtract 0.5 before standardizing the value specified.

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(25,5)  

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For this case we want to find this probability:

P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)

And if we use the z score given by:

z =\frac{x-\mu}{\sigma}

We got this:

P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)

And we can find this probability like this:

P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728

Part b

For this case we want this probability:

P(X \leq 30)

And if we use the continuity correction we got:

P(X \leq 30)= P(X

And using the z score we got:

P(X

Part c

For this case we want this probability:

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And if we use the continuity correction we got:

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Example:

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rearrange: 4x^2 + 16x + 4y^2 - 8y = 308

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=> (x^2 + 4x) + (y^2 - 2y) = 77

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5 0
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babymother [125]

Answer:

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Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

8 0
3 years ago
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