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3 years ago

5

Please asap help im desperate.......................

1 answer:

MrRa [10]3 years ago

8 0

Answer:

D

Step-by-step explanation:

What effect does Mathilde's losing the necklace have on the plot in "The Necklace"? It creates doubt in the mind of Madame Forestier' as to Mathidle's honesty. It helps extinguish Mathilde's longing for a life of luxury and wealth. It leads Mathilde and her husband into a life of debt, hard work, and poverty.

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Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)

jeyben [28]

Answer:

The vertex: $(\frac{3}{4},-\frac{41}{4} )$

The vertical intercept is: $y=-8$

The coordinates of the two intercepts of the parabola are $(\frac{3+\sqrt{41} }{4} , 0)$ and $(\frac{3-\sqrt{41} }{4} , 0)$

Step-by-step explanation:

To find the vertex of the parabola $4x^2-6x-8$ you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em> $a=4, b=-6, \:and \:c=-8$ </em>

2. You can apply this formula to find x-coordinate of the vertex

$x=-\frac{b}{2a}$ , so

$x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}$

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex ( $f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c$ )

$f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}$

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

$f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8$

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides}$

$x^2-6x-8+8=0+8$

$\mathrm{Simplify}$

$4x^2-6x=8$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2$

$\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{41}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

$x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}$

4 0

3 years ago

Find the product of (2/3)x and (1/2x²)+6x-3

kvasek [131]

Answer:

=

1

2

x2+

20

3

x−3

Step-by-step explanation:

3 0

2 years ago

A rectangle has an area of 144x^2-81. What is the length and the width?

Studentka2010 [4]

Answer:

thanks

Step-by-step explanation:

for asking this i need the answer too

6 0

2 years ago

Antonio runs 5 3/4 miles a day. After 5 days, how many miles has he completed

soldi70 [24.7K]

Step-by-step explanation:

No of miles a day = 5.75 miles

No of miles after 5 days = 5.75 x 5 = 28.75 miles

4 0

3 years ago

Find the value of y for the given value of x.

evablogger [386]

Y= -35
Y = -1

I put the work in the picture below!

(Hint: just substitute the x for its number and do simple adding and subtracting)

7 0

2 years ago